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2. A block of mass of 12.0 kg is sitting on a frictionless surface. If the...

2. A block of mass of 12.0 kg is sitting on a frictionless surface. If the block is initially at rest, and a force of 5.0 N parallel to the surface is applied for 13.0 seconds, what is the final speed of the block?

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Answer #1

Here,

let the final speed is v

using second law of motion

force * time = change in momentum

5 * 13 = 12 * (v - 0)

v = 5.42 m/s

the final speed of the block is 5.42 m/s

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