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What is the theoretical yield (in moles) of MgO that can be formed if you react...

What is the theoretical yield (in moles) of MgO that can be formed if you react 3.2 mol of O2 with an excess of magnesium? 2Mg(s) + O2(g) → 2MgO(s)

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Answer #1

Theoretical yield:

3.2 mole O2 X 2 mole of MgO/1 mole O2 = 6.4 mole of MgO.

Or

1 mole of O2 produced 2 moles MgO -from balanced equation

3.2 moles of O2 produce X mole of MgO

X= 3.2x2/1= 6.4 mole MgO

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