A thin-walled hollow cylinder is rolling on a surface. What fraction of its total kinetic energy...
A thin-walled hollow cylinder is rolling on a surface. What fraction of its total kinetic energy is in the form of rotational kinetic energy about the center of mass?
The answer is not 2/5.
Homework Answers
thin-walled hollow cylinder means moment of inertia , I is given as
I = mr2
v = rw ( no slip condition)
so,
rotational kinetic energy, KR = 1/2 * I * w2
KR = 1/2 * mr2 * v2 / r2
KR = 1/2mv2
so,
fraction = KR / KT where KT is total kinetic energy
fraction = 1/2mv2 / 1/2mv2 + 1/2mv2
fraction = 1/2
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