A sample has a mean of M = 36 and a standard deviation of s = 2. Find the z score for each of the following X values from this sample. (Use 1 decimal place.)
| X | z |
| 39.0 | |
| 41.0 | |
| 38.0 | |
| 31.0 | |
| 35.0 | |
| 32.0 |
Calculate the sample standard deviation for this data set: 11, 28, 36. The formula for the sample standard deviation is shown, where ?n represents the sample size, ?x represents each value in the data set, and ?⎯⎯⎯x¯ represents the sample mean. ?=∑(?−?⎯⎯⎯)2?−1‾‾‾‾‾‾‾‾‾‾‾‾√s=∑(x−x¯)2n−1 Step 1. Calculate the sample mean. ?⎯⎯⎯x¯ = Step 2. Calculate the deviations and the squares of the deviations. deviation of 11= square of deviation of 11= deviation of 28= square of deviation of 28= deviation of 36=...
A population has a mean of 55.5 and a standard deviation of 12.7. A sample of 72 will be taken. Find the probability that the sample mean will be between 51.1 and 56.3. smaller z score = Number (2 decimals) larger z score = Number (2 decimals) The probability = Number (use 4 decimals)
A variable has a mean of 100 and a standard deviation of 16. Sixteen observations of this variable have a mean of 113 and a sample standard deviation of 36. Determine the observed value of the a. standardized version of x. b. studentized version of x. a. Z= (Round to three decimal places as needed.) b.t- (Round to three decimal places as needed.) a. Use the one-mean t-interval procedure with the sample mean, sample size, sample standard deviation, and confidence...
Assume that you have a sample size of n1 = 16 with a mean of 42 and a standard deviation (S) equal to 9. Assume that you have another independent sample with n2 = 25, a mean of 36 and a standard deviation (S) of 4. Assume you are directed to use a significance level of α = 0.01. [DM.4] Construct the appropriate hypothesis test. Identify H0 and H1. What are the appropriate critical values? (4 Decimal Places) From what...
= X- 4) A normal distribution has mean u = 65 and a population standard deviation o= 20. Find and interpret the z - Score for x = 64. u a) The z - score for x = 64 is 64-65 b) Interpret these results. (Explain): 5) A sample size 28 will be drawn from a population with mean 120 and standard deviation 21. a) Is it appropriate to use the normal distribution to find probabilities for x? yes or...
Suppose a set of data has a sample mean of 106 and a sample standard deviation of 19.8. What is the Z-score for the value 122.0? Round the 2-score to two decimal places. Your Answer: Answer
1. A normal distribution has a mean of μ = 60 and a standard deviation of σ = 12. For each of the following samples, compute the z-score for the sample mean and determine whether the sample mean is a typical, representative value or an extreme value for a sample of this size. a. M = 53 for n = 4 scores σ/ √n= 12/√4 =6 z=(53-60)/6 = -1.17 b. M = 53 for n = 9 scores σ/ √n=...
A normally distributed population has a mean of µ = 70 and a standard deviation of σ = 12. A sample (n = 36) is selected from a population and a treatment is administered to the sample. After treatment, the sample mean is found to be M = 65. Does this sample provide evidence of a statistically significant treatment effect with an alpha of 0.05 (non-directional hypothesis)? [G&W Chp 8] Yes, our z-score reaches the critical region. No, our z-score fails to...
Consider a sample with a mean equal to 38 and a standard deviation equal to 12. Calculate the z-scores for the following values. a) 48 b) 62 c) 32 d) 12 a) The z-score of 48 is nothing. (Round to two decimal places as needed.) b) The z-score of 62 is nothing. (Round to two decimal places as needed.) c) The z-score of 32 is nothing. (Round to two decimal places as needed.) d) The z-score of 12 is
Consider a sample with a mean equal to 40 and a standard deviation equal to 12. Calculate the z-scores for the following values. a) 53 b) 68 c) 33 d) 9 (Round to two decimal places as needed.) a) The z-score of 53 is b) The z-score of 68 is (Round to two decimal places as needed.) c) The z-score of 33 is . (Round to two decimal places as needed.) (Round to two decimal places as needed.) d) The...