For Python debugExercise12.py is a recursive function that accepts an integer argument, n, and prints the...

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Question

For Python debugExercise12.py is a recursive function that accepts an integer argument, n, and prints the...

For Python

debugExercise12.py is a recursive function that accepts an integer argument, n, and prints the numbers 1 up through n.

By debugging these programs, you can gain expertise in program logic in general and the Python programming language in particular.

def main():
# Local variable
number = 0

# Get number as input from the user.
number = int(input('How many numbers to display? '))

# Display the numbers.
print_num(number)

# The print_num function is a a recursive function
# that accepts an integer argument, n , and prints
# the numbers 1 up through n.
def print_num(n):
if n > 1:
print_num(n + 1)
print (n, sep=' ')

# Call the main function.
main()

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Answer 1

Answer #1

def main():
    # Local variable
    number = 0

    # Get number as input from the user.
    number = int(input('How many numbers to display? '))

    # Display the numbers.
    print_num(number)

# The print_num function is a a recursive function
# that accepts an integer argument, n , and prints
# the numbers 1 up through n.
def print_num(n):
    if n > 0:
        print_num(n - 1)
        print (n, sep=' ')

# Call the main function.
main()

Add a comment

Answer 2

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