Question

Average volume of NaOH used (mL) Concentration CH3COOH in vinegar (mol/L) % CH3COOH in vinegar   5.7...

Average volume of NaOH used (mL)

Concentration CH3COOH in vinegar (mol/L)

% CH3COOH in vinegar  

5.7

.057

Average volume of NaOH used (mL)

Concentration CH3COOH in vinegar (mol/L)

% CH3COOH in vinegar  

5.7

.057

help???!?!?!?

0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
Average volume of NaOH used (mL) Concentration CH3COOH in vinegar (mol/L) % CH3COOH in vinegar   5.7...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • Initial NaOH Volume (mL) Final NaOH Volume (mL) Total Volume of NaOH Used (mL) - 9...

    Initial NaOH Volume (mL) Final NaOH Volume (mL) Total Volume of NaOH Used (mL) - 9 5 8.5 - 10 4 9.6 - 10 1.7 7.9 Average Volume of NaOH Used (mL): 8.7 Data Table 2: Concentration of CH3COOH in Vinegar Average Volume of NaOH Used (mL) Concentration CH3COOH in vinegar (mol/L) % CH3COOH in vinegar 8.7

  • fill in 5-9 A. Preparation of Vinegar Sample Brand of vinegar Trial 1 Trial 2 1....

    fill in 5-9 A. Preparation of Vinegar Sample Brand of vinegar Trial 1 Trial 2 1. Volume of vinegar used (mL) 2. Density of vinegar (g/mL) 3. Mass of vinegar used (g) solution - P.V. 5.0 1002 5.01 5.0 1.000 5.01 B. Analysis of Vinegar Sample 1. Buret reading of NaOH, initial (mL) 2. Buret reading of NaOH, final (mL) 3. Volume of NaOH used (mL) 0 0 43.60 46,90 42.60 41.90 1005 4. Molar concentration of NaOH (mol/L) 5....

  • Can you help me answer Question A? assuming 1.5M for NaOH Data Table 1. NaOH Titration...

    Can you help me answer Question A? assuming 1.5M for NaOH Data Table 1. NaOH Titration Volume. Trial 1 Trial 2 Trial 3 Initial NaOH Final NaOH Total volume of Volume (mL) Volume (mL) NaOH used (mL) 9.1 0 9.1 9.8 .8 9.0 9.9 1.2 8.7 Average Volume of NaOH Used (ml): 8.93 Data Table 2. Concentration of CH3COOH in Vinegar. Average volume of Concentration CH3COOH NaOH used (mL) in vinegar (mol/L) 8.93 0.89 % CH3COOH in vinegar 5.34 X...

  • A 52.0-mL volume of 0.350 mol L−1 CH3COOH (Ka=1.8×10−5) is titrated with 0.400 mol L−1 NaOH....

    A 52.0-mL volume of 0.350 mol L−1 CH3COOH (Ka=1.8×10−5) is titrated with 0.400 mol L−1 NaOH. Calculate the pH after the addition of 21.0 mL of NaOH.

  • 1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used...

    1. Volume of Vinegar used in each trial = 5.00 mL 2. Molarity of NaOH used in each trial = 0.20M 3. Volume of NaOH used in trail#1 (Final – Initial buret reading) = __17.80______ mL 4. Volume of NaOH used in trail#2 (Final – Initial buret reading) = ___18.20_____ mL 5. Average Volume of NaOH used = (#3 + #4) / 2 = ___18______ mL 6. Calculate Molarity of Acetic acid in vinegar = _________ M ?????? (molarity of...

  • Exercise 1 - Questions 1. The manufacturer of the vinegar used in the experiment stated that...

    Exercise 1 - Questions 1. The manufacturer of the vinegar used in the experiment stated that the vinegar contained 5.0% acetic acid. What is the percent error between your result and the manufacturer statement? Show your work 30 Using the following equation, determine the average concontration (moles per liter) of acetic acid (CH,COH) present in your vinegar. Record the concentration in Data Table 2 average volume of NaOH (ml) X 1L NaOH 1000 ml NaOH 0,5 mol NaOH 1L NOH...

  • A vinegar (acetic acid) solution of unknown concentration was titrated to the light pink endpoint with the standardized NaOH solution.

    A vinegar (acetic acid) solution of unknown concentration was titrated to the light pink endpoint with the standardized NaOH solution. The weight volume % of the vinegar solution were calculated. Molecular formula of Acetic acid: C2H4O2 Volume of vinegar sample titrated (ml) 5.00 Volume of NaOH required to neutralize vinegar in (mL) 8.74 Concentration of NaOH in mol/L, 0.1979 Calculate the weight/volume percentage of the vinegar solution (g/100 ml). 

  • 30 Using the following equation determine the average concentration (moles per liter) of acetic acid (CH,CO,H)...

    30 Using the following equation determine the average concentration (moles per liter) of acetic acid (CH,CO,H) present in your vinegar. Record the concentration in Data Table 2 average volume of NaOH (mL) X 1L NAOH 1000 mL NAOH 0,5 mol NaOH 1. NaOH 1 mol CH4COH 1 mol NaOH = average moles of CH,CO,H average moles of CH,CO,H 5.0 ml, vinegar 1000 ml IL = Concentration of CH.CO, H (M=mol/L) 31 Using the following equation and your result from Step...

  • A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar...

    A titration of vinegar with a solution of NaOH was performed. If 3.35 mL of vinegar needs 45.0 mL of 0.135 M NaOH to reach the equivalence point in a titration CH3COOH(aq)+NaOH(aq)→H2O(l)+NaC2H3O2(aq) Part A: Calculate the mass of acetic acid present in the vinegar sample? Part B: How many grams of acetic acid are in each mL of vinegar? Part C:How many grams of acetic acid would be in a 1.60 qt sample of this vinegar? Part D: How many...

  • Mass of Unknown: 873 NaOH Concentration 0-1349 M Volume NaOH Average NaOH used (mL) Volume (mL)...

    Mass of Unknown: 873 NaOH Concentration 0-1349 M Volume NaOH Average NaOH used (mL) Volume (mL) Run # 117m 1/. 067mL 9.7mし Be sure to show ALL of your work Determine the number of moles of unknown acid in your 25 mL sample-Show Calculations

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT