Question

A solution made by dissolving 150.0 g of an unknown compound in 425.0 mL of benzene...

A solution made by dissolving 150.0 g of an unknown compound in 425.0 mL of benzene to make a solution which has a freezing point 18.6 °C lower than that of pure benzene. Kf for benzene is 5.12 °C/m and the density of benzene is 0.877 g/mL.

b) The molality of the solution is 3.63. How many moles of the unknown compound were dissolved in the solution?

C) what is the molar mass of the unknown compound?

0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A solution made by dissolving 150.0 g of an unknown compound in 425.0 mL of benzene...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The molar mass of unknown molecular compound is determined using freezing point depression. The substance is...

    The molar mass of unknown molecular compound is determined using freezing point depression. The substance is dissolved in benzene (C6H), an organic solvent. Use the data below to determine the molar mass of the substance. 8.65 g Mass of unknown compound Freezing point of solution Volume of benzene -10.21°C 35.0 mL 5.53°C Freezing point of benzene Density of benzene Kf for benzene 0.8765 g/mL 5.12°C/m Molar mass = g/mol

  • Pure benzene, C6H6, has a molar mass of 78.114 g mol-1, a density of 0.8765 g...

    Pure benzene, C6H6, has a molar mass of 78.114 g mol-1, a density of 0.8765 g mL-1, a freezing point of 5.45°C, and a boiling point of 80.2°C. Its freezing point depression and boiling point elevation constants are: Kf = 5.07°C m-1; Kb = 2.53oC m-1. A solution was made by taking 33.88 g of an unknown nonelectrolyte and dissolving it in 175.0 g of benzene. The measured freezing point of the solution was 1.65oC. Calculate the molar mass of...

  • When 12.6-grams of an unknown compound is placed in 0.116-kg of benzene, the freezing point is...

    When 12.6-grams of an unknown compound is placed in 0.116-kg of benzene, the freezing point is changed by 2.34°C. The value of Kf= 4.90°C/m for benzene. Determine the molar mass of the unknown compound. Answer to 1 decimal place and include your units. Answer: Determine the molality of a solution when 32.3 grams of ethanol, C2H5OH (Molar mass = 46.08 g/mol) is dissolved in 0.947 kg of water. Answer to 2 decimal places. Answer: Find the freezing point of a...

  • A solution made by dissolving 85.0 g f sucrose (Molar mass. 342.3 g/mol) in 515 go...

    A solution made by dissolving 85.0 g f sucrose (Molar mass. 342.3 g/mol) in 515 go acetic acid at 25 degree C froze at 14.95degreeC. Freezing point of the pure acetic acid is 16.90degreeC.Density of acetic acid is 1.05 g/ml. at 25 degree C. Answer the following and show your work in the space provided. Molality of sucrose solution = K_i of acetic acid = 93.42 g of an unknown non-volatile, non-electrolyte solute was dissolved in 850.g of acetic acid....

  • Calculate the molar mass of naphthalene, the organic compound in mothballs, if a solution prepared by...

    Calculate the molar mass of naphthalene, the organic compound in mothballs, if a solution prepared by dissolving 7.50 g of naphthalene in exactly 150 g of benzene has a freezing point 2.0°C below that of pure benzene. (Kf of benzene is 5.12°C/m.)

  • A student made a solution by dissolving 0.144g of an unknown in 10.00g of benzene, C6H6,...

    A student made a solution by dissolving 0.144g of an unknown in 10.00g of benzene, C6H6, and found the vapor pressure solution to be 94.35mm Hg. The vapor pressure of pure benzene is 95.00mm Hg at the temperature of the experiment. (Show your work and use the factor labor method) a. what is the mole fraction of benzene in the solution? b. how many moles of benzene were in the solution? c. how many moles of unknown were in the...

  • The freezing point of a solution of 1.104 g of an unknown nonelectrolyte dissolved in 36.81...

    The freezing point of a solution of 1.104 g of an unknown nonelectrolyte dissolved in 36.81 g of benzene is 1.08°C. Pure benzene freezes at 5.48°C and its Kf value is 5.12°C/m. What is the molecular weight of the compound?

  • A solution is made by dissolving 58.125g of sample of an unknown, nonelectrolyte compound in water....

    A solution is made by dissolving 58.125g of sample of an unknown, nonelectrolyte compound in water. The mass of the solution is exactly 750.0g. The boiling point of this solution is 100.220 ∘C. What is the molecular weight of the unknown compound? Solvent Formula Kf value* (°C/m) Normal freezing point (°C) Kb value (°C/m) Normal boiling point (°C) water H2O 1.86 0.00 0.512 100.00 benzene C6H6 5.12 5.49 2.53 80.1 cyclohexane C6H12 20.8 6.59 2.92 80.7 ethanol C2H6O 1.99 –117.3...

  • 2. A solution of an unknown molecular substance is prepared by dissolving 0.50 g of the...

    2. A solution of an unknown molecular substance is prepared by dissolving 0.50 g of the unknown in 8.0 g of benzene. The solution freezes at 3.9°C. Determine the molar mass of the unknown. (Benzene has a freezing point of 5.5°C and a Kfvalue of 5.12°C/m) 10

  • 3. The density of a 4.53 M NH, solution is 0.9651 g/mL Calculate the molality 4....

    3. The density of a 4.53 M NH, solution is 0.9651 g/mL Calculate the molality 4. Calculate the freezing and boiling points of a solution made by mixing 10.5 g magnesium iodide with 150.0 g water. 5. A solution prepared by dissolving 0.56 g of a non-ionic solute in 25.0 g benzene freezes at 4.45°C. What is the molar mass of the solute?

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT