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How many grams of urea, (NH2)2CO (the product of protein metabolism in animals) must be dissolved...

How many grams of urea, (NH2)2CO (the product of protein metabolism in animals) must be dissolved in 146.3 g of H2O to cause a freezing point depression of 1.996 degrees celsius? Kf=1.86 C/m

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Answer #1

Ans :

Freezing point depression = kf x m

where m is molality

putting values :

1.996 = 1.86 x m

m = 1.073 m

molality = mol / mass of solvent in kg

1.073 = n / 0.1463

n = 0.157 mol

Mass of urea = mol x molar mass

= 0.157 mol x 60.06 g/mol

= 9.43 grams

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