Given that μX = 3 and σ2 over X = 16,
a) Let Y = 7X + 43 and find σ2 over Y: ___________ , and μY : ___________
b) Let Z = 7X + 60 and find σ2 over z : ________________ , and μZ : _______________
Solution-A:
mean(Y)=E(Y)=7*E(X)+43=7*3+43=64
μY =64
var(7X+43)=7^2*var(x)=7^2*16=784
ANSWER:
σ2=784
μY =64
Solution-B:
μZ=E(7X+60=7*E(X)+60=7*3+60=81
var(7X+60)=7^2*(var(X)=49*16=784
ANSWER:
σ2=784
μZ=81
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