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Methanol, CH3OH (l), combusts according to the following equation: 2 CH3OH (l) + 3 O2 (g)...

Methanol, CH3OH (l), combusts according to the following equation:

2 CH3OH (l) + 3 O2 (g) → 2 CO2 (g) + 4 H2O (l) ∆rHo (298 K) = −1452 kJ

Here is a list of Entropies of formation: S (J K-1 mol-1) at 298 K

CH3OH (l) =126.8

O2 (g) = 205.14

CO2 (g) = 213.74

H2O = (l) 69.91

(a) If the above reaction was used in a fuel cell, say, to perform work, what will be the maximum amount of non-expansion work that could theoretically be extracted from the cell per mole of methanol combusted? Explain.

(b) What is the minimum amount of heat (per mole of methanol combusted) which must flow to the surroundings in the above fuel cell? Explain.

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