A 1550 kg car coasts down a 20.4 m hill inclined at 5.00° below the horizontal. The force due to friction is 15.0 N. What is the total work done on the car?
A 1550 kg car coasts down a 20.4 m hill inclined at 5.00° below the horizontal....
A 5.00-kg package slides 2.60 m down a long ramp that is inclined at 25.0 ∘ below the horizontal. The coefficient of kinetic friction between the package and the ramp is μk = 0.370. A)Calculate the work done on the package by friction. B)Calculate the work done on the package by gravity. C)Calculate the work done on the package by the normal force. D)Calculate the total work done on the package. E)If the package has a speed of 2.60 m/s...
A driver coasts down a hill 200 m high with initial speed vo 35 m/s. The road has friction that results in a negative work -1.7 x 10° J. The effect of this is that the total initial energy is reduced by this amount by the time the car reaches the bottom of the hill. Calculate the speed of the car when it reaches the bottom of the hill. The mass of driver and passenger is 1750 kg 59.3 m/s...
A car of mass 1100 kg starts from rest at sea level and climbs a hill of height 50.0 m. At the top of the hill, the car has a speed of 25.0 m/s, and at this instant, the driver shuts off the engine of the car. The car then coasts down the other side of the hill to height of 15.0 m above sea level. Assume that friction and air resistance are negligibly small. a) (6 pts) How much...
A car of mass 1000 Kg descends a hill inclined with horizontal by 30°, the car is traveling at 80 km/h is uniformly brought to rest over a distance of 40 m. Calculate using work-energy method the average braking force required. The resistance to the motion is 200 N. 40 0 = 30°
a 1200kg car coasts from rest down a driveway that is inclined 20degrees. to the horizontal and is 15m long. how fast is the car going at the end of the delivery if.... (a) friction is negligible (book answer is 10m/s) (b) a friction force of 3000n opposes the motion? (book answer is 5.1 m/s) dont know where to begin to solve these 2questions. I tried differant formulas, but nothing I tried came out to the answers in the book....
Vo 5) h 200 m A driver coasts down a hill 200 m high with initial speed vo 40 m/s. The road has friction that results in a negative work -1.7 x 10 J. The effect of this is that the total initial energy is reduced by this amount by the time the car reaches the bottom of the hill. Calculate the speed of the car when it reaches the bottom of the hill. The mass of driver and passenger...
An 1100 kg car is shifted into neutral and coasts down a 10 meter hill and then back up a 15 meter hill. If you assume that frictional losses are negligible and the car starts out at 60 mph, what will its speed be when it reaches the top of the second hill? Use g 9.8 m/s2, 1 mile 1600 meters, and round answer to 2 significant figures. - Gas station 15 m 10 m
A 75 kg snowboarder slides down a hill that has a vertical drop of 6.0 m and is inclined at 31owith respect to the horizontal. The initial speed of the snowboarder at the top of the hill is 5.0 m/s. The coefficient of kinetic friction between the ramp and the snowboard is 0.20. A) Calculate the acceleration of the snowboarder The acceleration is 3.40 m/s B) Calculate the total work done on the snowboarder C) Using the work-energy theorem, calculate...
7. A 1300 kg car drives up a 17 m high hill (the elevation of the hill is 17 meters). During the drive two nonconservative forces do work on the car: the force of friction and the force generated by the car’s engine. The work done by friction adds 331 kJ to the internal energy. The work done by the engine is 634 kJ. (a) What is the change in the car’s kinetic energy? (b) If the car started up...
work , energy and power
120 m A boy rides a soapbox car down a hill as shown. The total mass of the 60 m boy and the car is 50 kg. If 1 000) of work are done against friction, the total kinetic energy of car and rider at the bottom is