A Mountain bar has a mass of 6.9×10−2 kg and a calorie rating of 320 Cal .
What speed would this candy bar have if its kinetic energy were equal to its metabolic energy? [Note: The nutritional calorie, 1 Cal, is equivalent to 1000 calories (1000 cal) as defined in physics. In addition, the conversion factor between calories and joules is as follows: 1 Cal = 1000 cal = 1 kcal = 4186 J.]
Express your answer using two significant figures.
Mass of the bar, m = 6.9 * 10^-2 kg = 0.069 kg
Metabolic energy, E = 320 nutritional calories
= 320 * 1000 cal
= 320 * 4186 J
Kinetic energy = metabolic energy
(1/2) m v^2 = 320 * 4186
v^2 = 320 * 4186 * 2 / 0.069
Hence,
v = 6231.10 m/s = 6.23 km/s
A Mountain bar has a mass of 6.9×10−2 kg and a calorie rating of 320 Cal...
can someone please help me solve this lab?
calorie since it takes 1.00 cal to rai at units for the amount of heat may be The specific heat of water is used to define the value of a calorie since it takes 1 the temperature of 1 gram of water 1°C. The measurement units for the amount converted using the conversion factor: 1 calorie = 4.184 Joules. The specific heats of several substances are shown in Table 1. Notice that...