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You extract a 1.00mL sample of water from a creek near a chemical plant. You treat...

You extract a 1.00mL sample of water from a creek near a chemical plant. You treat the sample with NaCl and isolate 0.00185g of lead (II) chloride. What was the initial concentration of lead in your sample in M?

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Answer #1

MW of lead (II) chloride = 278.1

So, 0.00185 g of lead (II) chloride = 278.1 x 0.00185 mole = 6.65 x 10-6 mole of lead (II) chloride

Then, 1 mL of water sample contain 6.65 x 10-6 mole of lead

So, 1000 mL of water sample contain 6.65 x 10-6 x 1000 = 6.65 x 10-3 mole of lead

ANSWER :   Concentration of lead in water sample is 6.65 x 10-3 M or 0.00665 M

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