You extract a 1.00mL sample of water from a creek near a chemical plant. You treat the sample with NaCl and isolate 0.00185g of lead (II) chloride. What was the initial concentration of lead in your sample in M?
MW of lead (II) chloride = 278.1
So, 0.00185 g of lead (II) chloride = 278.1 x 0.00185 mole = 6.65 x 10-6 mole of lead (II) chloride
Then, 1 mL of water sample contain 6.65 x 10-6 mole of lead
So, 1000 mL of water sample contain 6.65 x 10-6 x 1000 = 6.65 x 10-3 mole of lead
ANSWER : Concentration of lead in water sample is 6.65 x 10-3 M or 0.00665 M
You extract a 1.00mL sample of water from a creek near a chemical plant. You treat...
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