Question

Correct the five syntax, run-time or logic errors that are found in the CountAndAverageNumbers.java file. Link to the file: CountAndAverageNumbers.javaPreview the document. Make sure you include comments in your code where errors were corrected. If you do not flag each error with a comment, points will be deducted. Upload the corrected .java file here. The output of the corrected file looks like the following: Debug4Output.PNG This program reads an unspecified number of integers, determines how many positive and negative values have been read, and computes the total and average of the input values (not counting zeros). The program ends with the input 0. The average is displayed as a double. */ import java.util.Scanner; public class CountAndAverageNumbers { public static void main(String[] args) { int countPositive = 0, countNegative = 0; int count = 0, number; total = 0; Scanner input = new Scanner(System.in); System.out.print("Enter an integer, the input ends if it is 0: "); number = input.nextInt(); while (number = 0) if (number > 0) countPositive++; else if (number < 0) countNegative++; total += number; count--; // Read the next number System.out.print("Enter an integer, the input ends if it is 0: "); number = input.nextInt(); if (count != 0) System.out.println("No numbers are entered except 0"); else { System.out.println("The number of positives is " + countPositive); System.out.println("The number of negatives is " + countNegative); System.out.println("The total is " + total); System.out.println("The average is " + total / count); } } } Output: Enter an integer, the input ends if it is 0: 5 Enter an integer, the input ends if it is 0: 2 Enter an integer, the input ends if it is 0: 18 Enter an integer, the input ends if it is 0: -6 Enter an integer, the input ends if it is 0: -4 Enter an integer, the input ends if it is 0:3 Enter an integer, the input ends if it is 0:-8 Enter an integer, the input ends if it is 0:12 Enter an integer, the input ends if it is 0: 0 The number of positivies is 4 The number of negatives is 3 The total is 20.0 The average is 2.857142857142857.

Download CountAndAverageNumbers.java

This program reads an unspecified number of integers, determines how many positive
and negative values have been read, and computes the total and average of the input values
(not counting zeros). The program ends with the input 0. The average is displayed as a double.
*/
import java.util.Scanner;

public class CountAndAverageNumbers {
public static void main(String[] args) {
int countPositive = 0, countNegative = 0;
int count = 0, number;
total = 0;

Scanner input = new Scanner(System.in);
System.out.print("Enter an integer, the input ends if it is 0: ");
number = input.nextInt();

while (number = 0)
if (number > 0)
countPositive++;
else if (number < 0)
countNegative++;

total += number;
count--;
  
// Read the next number
System.out.print("Enter an integer, the input ends if it is 0: ");
number = input.nextInt();

if (count != 0)
System.out.println("No numbers are entered except 0");
else {
System.out.println("The number of positives is " + countPositive);
System.out.println("The number of negatives is " + countNegative);
System.out.println("The total is " + total);
System.out.println("The average is " + total / count);
}
}
}

Answer 1

 package test; import java.util.Arrays; import java.util.Scanner; public class CountAndAverageNumbers {        public static void main(String[] args) {                int countPositive = 0, countNegative = 0,zerocount=0;           int count = 0, number;          int total = 0;          Scanner input = new Scanner(System.in);                 System.out.println("Enter the number of elements for the array:");              int n = input.nextInt(); //Setting the size of array            int arr1[] = new int[n]; //Initializing the array               System.out.println("Enter elements: ");                 for(int i=0;i<arr1.length;i++) {                     arr1[i] = input.nextInt(); //Adding the elements to array               }               System.out.println(Arrays.toString(arr1));              for(int i=0;i<arr1.length;i++) { //This for loop counts for positives if >0 and                   if(arr1[i]>0) { // negatives if <0 and zeros if both the above statements are not satisfied                               countPositive++;                        }else if(arr1[i]<0) {                                countNegative++;                        }else {                                 zerocount++;                    }               }               System.out.println("Number of positive elements are:"+countPositive);           System.out.println("Number of negative elements are:"+countNegative);           System.out.println("Number of zeroes are:"+zerocount);  } } 

Hi,

Instead of directly taking numbers, i have taken an array and stored the elements. Then, looped through the array and counted number of positives and negatives along with zeroes. Please feel free to comment if you need more info or if you find some doubts.