A wire forms a halfcircle of radius R = 70cm and two (radial) straight segments each...
A wire forms a halfcircle of radius R = 70cm and two (radial) straight segments each of length L = 54cm. The wire carries current i = 21mA. What is the magnitude of the net magnetic field at the semicircle's center in terms of uT? Note: The constant μo is equal to 4 Pi x 10-7 Tm/A
Homework Answers
Given Data
radius = 70 cm = 0.7 m
Length of the segment , L = 54 cm
current, i = 21 mA = 21*10^-3 A
Solution :-
The net magnetic field B = B1+ B2 + B3
but B1 = B3 = 0 (because it has no magnetic field)
B = B1 + B2 + B3
= 0 + (μ0/4π)(iπ/R) + 0
= μ0*i / 4*R
= (1*10^-7)*(21*10^-3)*π / 0.7
= 9.42*10^-9 T
= 0.00942 μT
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