z is a standard normal random variable. The P(-1.8<z<2.09) equals Group of answer choices 0.0176 0.9641...

Question

Question

z is a standard normal random variable. The P(-1.8<z<2.09) equals

Group of answer choices

0.0176

0.9641

0.9458

1.02

math Statistics-And-Probability

Answer 1

Answer #1

solution

P(-1.8<z<2.09)

= P(Z <2.09 ) - P(Z <-1.8 )

Using z table,

= 0.9817 -0.0359

=0.9458

probability=0.9458

Answer 2

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