Question

Python code.. Nine coins are placed in a 3x3 matrix with some face up and some face down. You can represent the state of the coins with the values 0 and 1.

000

010

000

etc.

Each state can also be represented using a binary number. For example, the preceding matrices correspond to the numbers: 000010000 There are a total of 512 possibilites. So, you can use the decimal numbers 0,1,2,3 etc., and 511 to represent all states of the matrix. Write a program that prompts the user to enter a number between 0 and 511 and displays the corresponding 3x3 matrix with the character H and T. 0 represents H and 1 represents T.

def decimaltobinary(number):
binary = ""
  
while (number >= 1):
number, remainder = divmod(number, 2)
binary = binary + str(remainder)
return binary

def main():
number = eval(input("Enter a number between 0 and 511: "))
binary = decimaltobinary(number)
binary = list(binary.zfill(9))
binary = list(map(int, binary))
final_list = ['T' if x == 1 else 'H' for x in binary]
  
for i in range(3):
print(" ".join(final_list[i*3:(i+1)*3]))
  
main()

Answer 1

 num = str(bin(int(input("Enter a number between 0 and 511: "))).replace("0b", "")) #Converting user input number to binary and then to string fill = 9 - len(num) for i in range(1, fill+1): #Filling leading zeroes of binary with H in matrix if(i%3 == 0): print("H") else: print("H", end=" ") for i in range(1, len(num)+1): #Filling rest matrix with corresponding H or T if((fill+i)%3 == 0): if num[i-1] == '0': print("H") else: print("T") elif num[i-1] == '0': print("H", end=" ") else: print("T", end=" ")