In a past presidential election, 39,885,048. people voted for Candidate A; 39,660,675 Candidate B; and 193,670...
In a past presidential election, 39,885,048. people voted for Candidate A; 39,660,675 Candidate B; and 193,670 for third-party candidates.
a. What percentage of voters chose Candidate A? Find the % of voters who chose Candidate A Answer _____%
b. Would it be appropriate to find a confidence interval of voters choosing Candidate A? (Answer is A,B,C or D)
A.Yes, it is appropriate to find a confidence interval because the proportion is a sample proportion and the conditions for the Central Limit Theorem are met.
B.No, it is not appropriate to find a confidence interval because there are three possible outcomes for each observation.
C.No, it is not appropriate to find a confidence interval because the proportion is a population proportion.
D.No, it is not appropriate to find a confidence interval because the conditions for the Central Limit Theorem are met
Homework Answers
a) Percentage of voters chose Candidate A = 39885048 / (39885048 + 39660675 + 193670) = 0.5002 = 50.02%
b) No, it is not appropriate to find a confidence interval because the proportion is a population proportion. Option C is correct.
Add Answer to:
In a past presidential election, 39,885,048. people voted for
Candidate A; 39,660,675 Candidate B; and 193,670...
5) In a recent presidential election, 500 voters were surveyed and 350 of them said that...
5) In a recent presidential election, 500 voters were surveyed and 350 of them said that they voted for the candidate who won. a. Construct a 96% confidence interval estimate of the percentage of voters who said they voted for the candidate who won. b. How many voters must they survey if they want 90% confidence that the sample proportion is in error by no more than 0.02?
In a survey of 1425 people, 1045 people said they voted in a recent presidential election....
In a survey of 1425 people, 1045 people said they voted in a recent presidential election. Voting records show that 71% of eligible voters actually did vote. Given that 71% of eligible voters actually did vote, (a) find the probability that among 1425 randomly selected voters, at least 1045 actually did vote. (b) What do the results from part (a) suggest?
In a survey of 13181318 people, 877877 people said they voted in a recent presidential election....
In a survey of 13181318 people, 877877 people said they voted in a recent presidential election. Voting records show that 6464% of eligible voters actually did vote. Given that 6464% of eligible voters actually did vote, (a) find the probability that among 13181318 randomly selected voters, at least 877877 actually did vote. (b) What do the results from part (a) suggest?
In a survey of 1145 people, 862 people said they voted in a recent presidential election....
In a survey of 1145 people, 862 people said they voted in a recent presidential election. Voting records show that 73% of eligible voters actually did vote. Given that 73% of eligible voters actually did vote, (a) find the probability that among 1145 randomly selected voters, at least 862 actually did vote. (b) What do the results from part (a) suggest? (a) P(X>862)=
Nine hundred registered voters are surveyed before a presidential election. Four hundred and eightysix say they...
Nine hundred registered voters are surveyed before a presidential election. Four hundred and eightysix say they will vote for candidate X. Construct a 95% confidence interval for the proportion of registered voters who will vote for candidate X.
To estimate the portion of voters who plan to vote for the Rebublican presidential candidate in...
To estimate the portion of voters who plan to vote for the Rebublican presidential candidate in the upcoming election, a random sample of likely voters of size n is to be chosen. Let θ be the proportion of voters who plan to vote for the Rebublican candidate. a. How large does n need to be so that the poll has 90% confidence interval with 2% margin of error? b. How large does n need to be so that the poll...
In a survey of 1127 people, 739 people said they voted in a recent presidential election....
In a survey of 1127 people, 739 people said they voted in a recent presidential election. Voting records show that 63% of eligible voters actually did vote. Given that 63% of eligible voters actually did vote, (a) find the probability that among 1127 randomly selected voters, at least 739 actually did vote. (b) What do the results from part (a) suggest? (a) P(x≥739) = b) What does the result from part (a) suggest? A.People are being honest because the probability...
1107 people, 816 people said they voted in a recent presidential election. Voting records show that...
1107 people, 816 people said they voted in a recent presidential election. Voting records show that 71% of eligible voters actually did vote. Given that 71% of eligible voters actually did vote, (a) find the probability that among 1107 randomly selected voters, at least 816 actually did vote. (b) What do the results from part (a) suggest? (a) P(X ≥816) ? round 4 decimals
In a survey of 1466 people, 1049 people said they voted in a recent presidential election....
In a survey of 1466 people, 1049 people said they voted in a recent presidential election. Voting records show that 69% of eligible voters actually did vote. Given that 69% of eligible voters actually did vote, (a) find the probability that among 1466 randomly selected voters, at least 1049 actually did vote. (b) What do the results from part (a) suggest? (a) P(X2 1049) = (Round to four decimal places as needed.) (b) What does the result from part (a)...
In a past presidential election, the actual voter turnout was 62%. In a survey, 882 subjects...
In a past presidential election, the actual voter turnout was 62%. In a survey, 882 subjects were asked if they voted in the presidential election. Find the mean and standard deviation for the numbers of actual voters in groups of 882. (Round answer to one decimal place.) = 546.84 (Round answer to two decimal places.) 14.42 = Give the interval of usual values for the number of voters in groups of 882. (Enter answer as an interval using square-brackets only...
In a survey of 1466 people, 1049 people said they voted in a recent presidential election. Voting records show that 69% of eligible voters actually did vote. Given that 69% of eligible voters actually did vote, (a) find the probability that among 1466 randomly selected voters, at least 1049 actually did vote. (b) What do the results from part (a) suggest? (a) P(X2 1049) = (Round to four decimal places as needed.) (b) What does the result from part (a)...
In a past presidential election, the actual voter turnout was 62%. In a survey, 882 subjects were asked if they voted in the presidential election. Find the mean and standard deviation for the numbers of actual voters in groups of 882. (Round answer to one decimal place.) = 546.84 (Round answer to two decimal places.) 14.42 = Give the interval of usual values for the number of voters in groups of 882. (Enter answer as an interval using square-brackets only...
Most questions answered within 3 hours.
-
Where is the error in this code sequence?
String s1 = "Hello";
String s2 = "ello";...
asked 10 months ago -
Financial data for Joel de Paris, Inc., for last year
follow:
Joel de Paris, Inc.
Balance...
asked 10 months ago -
Consider this reaction:
Al2(SO4)3 (aq)+ BaCl3
(aq) Al2Cl6 (aq)- +
3BaSO4(s) . What is the...
asked 10 months ago -
Suppose that Savneet is considering increasing her
recent random sample from 20 car rentals to 40...
asked 10 months ago -
Trucks arrive at an unloading terminal at an average rate of 120
per hour.
Trucks arrive...
asked 10 months ago -
Why are methanol and ethanol completely soluble in water while
octanol is not very little soluble....
asked 10 months ago -
A facilities manager at a university reads in a research report
that the mean amount of...
asked 10 months ago -
When the CuSO4 is rehydrated by adding water to the anhydrous
compound, is this an endothermic...
asked 10 months ago -
A ray of sunlight is passing from diamond into crown glass; the
angle of incidence is...
asked 10 months ago -
A block of mass 0.249 kg is placed on top of a light, vertical
spring of...
asked 10 months ago -
how do the kidneys compensate in the presences of acidosis
a) trigger hyperventilate
b) reserve acid...
asked 10 months ago -
Question 501 pts
The rental rate of capital to the firm increases. Which of the
following...
asked 10 months ago