If an energy storage system is capable of providing 10 kW at 80 % efficiency, the...
If an energy storage system is capable of providing 10 kW at 80 % efficiency, the total energy capacity required to provide 8 hours of operation is
Answer: 100kWh
Homework Answers
10 KW or 10,000 joules / sec
in 8 hour total energy
8 hour = 28800 sec
= 10,000 * 28800
= 2.88*10^8 joules
this is 80% energy
efficiency = 80%
so, energy =
= (2.88*10^8 / 80 )*100
3.6*10^8
in Kwh
1 Kwh = 2.8*10^-7
3.6*10^8*2.8*10^-7
= 100.8 KWh
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