KOH (concentration = 0.2205 M) is used in a titration to determine the amount of acetic...
KOH (concentration = 0.2205 M) is used in a titration to determine the amount of acetic acid (CH3COOH) in vinegar!
50 mL of vinegar was diluted to 500 mL in a volumetric flask. 25 mL of the diluted vinegar solution was titrated five times with the KOH.
The concentration of acetic acid in the DILUTED vinegar sample is 0.2171 M
Calculate the concentration of acetic acid in the ORIGINAL vinegar solution
Give your answer in g/L
MM CH3COOH = 60.05 g/mol
Give answer to 4 s.f.
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KOH (concentration = 0.2205 M) is used in a titration to
determine the amount of acetic...
A sample of vinegar is analyzed to determine its acetic acid concentration as mass percent. an...
A sample of vinegar is analyzed to determine its acetic acid concentration as mass percent. an analyze is prepared by diluting 15 mL of the original vinegar to 100 mL in a volumetric flask. Then, a 25 mL aliquot of this analyze is titrated with 0.1022M NaOH. if the titration endpoint is 31.23 mL, calculate the mass percent of acetic acid in the original sample.
40.0 ml of an acetic acid of unknown concentration is titrated with 0.100 M NaOH. After...
40.0 ml of an acetic acid of unknown concentration is titrated with 0.100 M NaOH. After 20.0 mL of the base solution has been added, the pH in the titration flask is 5.10. What was the concentration of the original acetic acid solution? [Ka(CH3COOH) = 1.8 × 10–5]
You diluted a 12.96 ml vinegar sample into a 100 ml volumetric flask with distilled water....
You diluted a 12.96 ml vinegar sample into a 100 ml volumetric flask with distilled water. You titrated a 25.00 mL aliquot of that solution and determined the concentration of acetic acid to 0.048 M. What was the concentration of acetic in the original sample.
I need it right now, please help me?? PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The...
I
need it right now, please help me??
PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The vinegar solution must be diluted by a factor of 5 to be suitable for titration. 1. Obtain - 20 ml of the stock vinegar solution from the fume hood. 2. Using the 10-ml. pipet, pipet" 10 mL of the stock solution to a 50-ml volumetric flask. 3. Fill the volumetric flask to the calibration line with distilled water. Be sure not to go over...
a-c 5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor)...
a-c
5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
4. Mr. Burnes bought a bottle of vinegar and wondered how concentrated the acetic acid (CH-COOH;...
4. Mr. Burnes bought a bottle of vinegar and wondered how concentrated the acetic acid (CH-COOH; mm = 60.05 g/mol) was inside. He titrated it with 0.00182 M NaOH that he found in a general chemistry laboratory. It took 9.90 mL of NaOH to reach the equivalence point. See titration curve on next page. A. What is the concentration of acetic acid if 23.7 mL of vinegar was used for the titration? B. Mr. Burnes bought the economy size bottle...
a 25.0 ml aliquot of vinegar was diluted to 250 ml in volumetric flask. Titration of...
a 25.0 ml aliquot of vinegar was diluted to 250 ml in volumetric flask. Titration of 50.0 ml aliquots of diluted solution required an average of 34.88 ml of 0.09600 M NaOH. Express the acidity of the vinegar in terms of percentage (w/v) of acetic acid.
1. In the second step she prepared the vinegar solution for the titration in the following...
1. In the second step she prepared the vinegar solution for the titration in the following manner 25.0 mL of vinegar were diluted to 250.0 mL in a volumetric flask, and 25.0 mL of this diluted solu- tion required 8.27 mL of the above standardized NaOH (gquestion 5a) to reach the phenolphthalein endpoint. What is the molarity of the acid as it was titrated (diluted vinegar)? a. Use the dilution equation to determine the molarity of the acid prior to...
i need help with questions for part b only please ZULU Acid-Base Titration (worksheet to be...
i need help with questions for part b only please
ZULU Acid-Base Titration (worksheet to be completed in pairs - dee via e-mail Thursday, April 2, 11:59 pm) Concentration of NaOH: 0.0993 mol/L Part A: The following data was obtained when a 20.00 mL sample of acetic acid was titrated with 0.0993 mol/L sodium hydroxide (NaOH). The indicator changed color when 18.90 mL of NAOH was added (highlighted below). pH pH Volume of Base (mL) 1.00 2.00 Volume of Base...
50.00-ml. sample containing acetic acid (CH.COOH, F.W. 60.05) was transferred into a 550.0-ml. volumetric flask and...
50.00-ml. sample containing acetic acid (CH.COOH, F.W. 60.05) was transferred into a 550.0-ml. volumetric flask and diluted to the mark with water. A 25.00-ml portion of the dilute solution was titrated with 25.47 mL of 0.1012 M NaOH solution to the end point. Calculate the "% (w/v) of acetic acid in the sample. Keep appropriate number of significant figures for the result. (10 points)
I
need it right now, please help me??
PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The vinegar solution must be diluted by a factor of 5 to be suitable for titration. 1. Obtain - 20 ml of the stock vinegar solution from the fume hood. 2. Using the 10-ml. pipet, pipet" 10 mL of the stock solution to a 50-ml volumetric flask. 3. Fill the volumetric flask to the calibration line with distilled water. Be sure not to go over...
a-c
5, Vinegar should contain more than 4% acetic acid (CHCOOH, molar mass 60.0 g mor) 25.0 mL of vinegar are diluted to 100.0 mL and 10.0 mL samples of this solution are titrated against 0.100 mol L-NaOH solution. An average of 18.1 mL NaOH are required to neutralize the vinegar. You will need to calculate the concentration of the diluted solution and hence the percentage concentration of acetic acid in the original vinegar via the following questions: CH COOH(aq)...
4. Mr. Burnes bought a bottle of vinegar and wondered how concentrated the acetic acid (CH-COOH; mm = 60.05 g/mol) was inside. He titrated it with 0.00182 M NaOH that he found in a general chemistry laboratory. It took 9.90 mL of NaOH to reach the equivalence point. See titration curve on next page. A. What is the concentration of acetic acid if 23.7 mL of vinegar was used for the titration? B. Mr. Burnes bought the economy size bottle...
1. In the second step she prepared the vinegar solution for the titration in the following manner 25.0 mL of vinegar were diluted to 250.0 mL in a volumetric flask, and 25.0 mL of this diluted solu- tion required 8.27 mL of the above standardized NaOH (gquestion 5a) to reach the phenolphthalein endpoint. What is the molarity of the acid as it was titrated (diluted vinegar)? a. Use the dilution equation to determine the molarity of the acid prior to...
i need help with questions for part b only please
ZULU Acid-Base Titration (worksheet to be completed in pairs - dee via e-mail Thursday, April 2, 11:59 pm) Concentration of NaOH: 0.0993 mol/L Part A: The following data was obtained when a 20.00 mL sample of acetic acid was titrated with 0.0993 mol/L sodium hydroxide (NaOH). The indicator changed color when 18.90 mL of NAOH was added (highlighted below). pH pH Volume of Base (mL) 1.00 2.00 Volume of Base...
50.00-ml. sample containing acetic acid (CH.COOH, F.W. 60.05) was transferred into a 550.0-ml. volumetric flask and diluted to the mark with water. A 25.00-ml portion of the dilute solution was titrated with 25.47 mL of 0.1012 M NaOH solution to the end point. Calculate the "% (w/v) of acetic acid in the sample. Keep appropriate number of significant figures for the result. (10 points)
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