Question

Calculate the volume (mL) of 3 methyl-1-butanol (0.809 g/mL) and glacial acetic acid (1.049 g/mL) by using the densities and moles. Please show your work. 3-methyl-1-butanol= 0.12 moles (molecular weight= 88.15 g/mol) & glacial acetic acid =0.24 moles (molecular weight=60.052 g/mol)

Answer 1

3- methyl-1-butanol:

No. Of mol = mass/ molar mass

Mass = n * molar mass

Mass = 0.12 mol * 88.15 g/ mol

= 10.578 g

Density = mass / volume

Volume = mass / density

V= 10.578 g / 0.809 g/mL

V = 8.557 mL.

Acetic acid:

Mass = 0.24 mol * 60.052 g/mL

= 14.412 g.

V = 14.412 g / 1.049 g/mL

V = 15.1189 mL

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