Question

Z is a standard normal variable. Find the value of Z in the following. Use 2 decimal places a. The area between 0 and Z is 0.3554. b. The area to the right of -Z is 0.8508. c. The area to the left of -Z is 0.1423 d. The area between -Z and Z is 0.8354 e. The area to the left of Z is 0.9803.

Answer 1

Using standard normal table,

(a)

P(0 < Z < 1.06) = 0.3554

value of z = 1.06

(b)

P(Z > -1.04) = 0.8508

value of z = -1.04

(c)

P(Z < 1.07) = 0.1423

The value of z = 1.07

(d)

value of z = 1.39

(e)

Value of z = 2.06