Question

In five tests, one student averaged 63.2 with a standard deviation of 3.3 while another student average 78.8 with a standard deviation of 5.3 Which student is relatively more consistent?

Answer 1

First student has mean = 63.2 and standard deviation = 3.3

so coefficient of variation =( standard deviation/mean) * 100 %

Coefficient of variation = 3.3/63.2*100 %

Coefficient of variation = 5.22%

Second student has mean = 78.8 and standard deviation = 5.3

Coefficient of variation ( second student) = 5.3/78.8 *100%

Coefficient of variation ( second student ) = 6.73%

The having low coefficient of variation is more consistent.

So first student is more consistent.