Code in prolog a predicate windows/3 that returns the list of all windows (sublists of consecutive...
Code in prolog a predicate windows/3 that returns the list of
all windows (sublists of consecutive elements)
of length 3 of the given list.
?- windows([1,3,a,4,b],Ys).
Ys = [[1,3,a],[3,a,4],[a,4,b]]
?- windows([1,3],Ys).
Ys = []
Homework Answers
`Hey,
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Here's the code:
windows([_], []).
windows([_, _], []).
windows([A, B, C | L], [[A, B, C] | Gs]) :-
windows([B, C | L], Gs).
The base case is when the list has one or two elements. In other case, we need to append the first three of the given list to Ys and recur for the first two + the remaining list.
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