Question

The mechanism for the decomposition of NO2Cl

The mechanism for the decomposition of NO2Cl is:
k-1

<---
NO2Cl --->NO2 + Cl
k1

k2
NO2Cl + Cl ---> NO2 + Cl2

By making a steady-state approximation for [Cl], express the rate of appearance of Cl2
in terms of the concentrations of NO2Cl and NO2.

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Answer #1

Steady state approximation:

d[Cl]/dt = k1[NO2Cl] - k-1[NO2][Cl] - k2[NO2Cl][Cl] = 0

k1[NO2Cl] = [Cl] x (k-1[NO2] + k2[NO2Cl])

[Cl] = k1[NO2Cl]/(k-1[NO2] + k2[NO2Cl])

Rate of appearance of Cl2

= d[Cl2]/dt = k2[NO2Cl][Cl]

= k1k2[NO2Cl]2/(k-1[NO2] + k2[NO2Cl])

answered by: jack wilson
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