Sample Size: 52
Determine if there is sufficient evidence to conclude the average amount of births is over 5000 in the United States and territories at the 0.05 level of significance.
LIVE BIRTHS
| Mean | 6911 |
| Median | 4750 |
| Standard Deviation | 8161.31 |
| Minimum | 582 |
| Maximum | 46,424 |
DEATHS
| Mean | 3958 |
| Median | 2964 |
|
Standard Deviation |
4039.60 |
| Minimum | 280 |
| Maximum | 19,767 |
MARRIAGES
| Mean | 3876 |
| Median | 2792 |
| Standard deviation | 4424.42 |
| Minimum | 215 |
| Maximum | 21,368 |
DIVORCES
| Mean | 1587 |
| Median | 1340 |
| Standard Deviation | 1427.25 |
| Minimum | 98 |
| Maximum | 6400 |
Sample Size: 52 Determine if there is sufficient evidence to conclude the average amount of births...
Sample size: 52 Determine if there is sufficient evidence to conclude the average amount of divorces is less than or equal to 4000 in the United States and territories at the 0.10 level of significance. Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your conclusion means in context of the data. LIVE BIRTHS Mean 6911 Median...
Determine if there is sufficient evidence to conclude the average amount of divorces is less than or equal to 4000 in the United States and territories at the 0.10 level of significance. Summary Table for Divorces AVERAGE 1,487 MEDIAN 1,118 STANDARD DEVIATION 1528.92805 MAX 7,627 MIN 71 Clearly state a null and alternative hypothesis Give the value of the test statistic n=52 Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what...
Determine if there is sufficient evidence to conclude the average amount of marriages is greater or equal to 2500 in the United States and territories at the .05 level of significance. Summary Table for Marriages AVERAGE 2,758 MEDIAN 1,602 STANDARD DEVIATION 3758.19448 MAX 17,398 MIN 114 Clearly state a null and alternative hypothesis Give the value of the test statistic n=52 Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null) Explain what your...
Summary Table for _Live births__for all 52 states___ Mean 302.12 Median 90.5 Standard Deviation 140,98 Minimum 556 Maximum 56,889 Summary Table for _Live births___Deaths__ Mean 306.36 Median 201.5 Standard Deviation 788, 64 Minimum 472 Maximum 39,12 Summary Table for _Live births_____Marriages__ Mean 418.97 Median 155 Standard Deviation 136,74 Minimum 405 Maximum 25, 490 Summary Table for _Live births___Divorces____ Mean 272.72 Median 160 Standard Deviation 8.23 Minimum 222 Maximum 18, 187 Hypothesis Testing Determine if there is sufficient evidence to conclude...
Summary Table for Live Births Mean 6,918 Median 4,728 Standard Deviation 8373.34169 Minimum 544 Maximum 46,738 Summary Table of Deaths Mean 4,159 Median 2,904 Standard Deviation 4266.55942 Minimum 290 Maximum 21,073 Summary Table for Marriages Mean 2,895 Median 2,011 Standard Deviation 3269.10487 Minimum 96 Maximum 14,133 Summary Table for Divorces Mean 1,334 Median 1,217 Standard Deviation 1344.26145 Minimum 0 Maximum 6,249 Determine if there is sufficient evidence to conclude the average amount of marriages is greater or equal to 2500...
Question: Hypothesis Testing test the following: Hypothesis Testing test the following: Determine if there is sufficient evidence to conclude the average amount of births is over 8000 in the United States and territories at the 0.05 level of significance. Sample Size is 52 (states and US territories) Mean: 6,869 Median: 6,869 Standard Deviation: 8,100 Minimum: 569 Maximum : 45,805 Clearly state a null and alternative hypothesis. Give the value of the test statistic. Report the P-Value. Clearly state your conclusion...
Summary for Births Mean 7046.54 Median 4936 Standard Deviation 8358 simple size is 52 Minimum 519 Maximum 46117 Determine if there is sufficient evidence to conclude the average amount of births is greater or equal to 7000 in the United States and territories at the .05 level of significance. Clearly state a null and alternative hypothesis Give the value of the test statistic Report the P-Value Clearly state your conclusion (Reject the Null or Fail to Reject the Null)...