Question

A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 39.0 m/s ; when it leaves the bat, the ball is traveling to the left at an angle of 29.0 ∘ above horizontal with a speed of 59.0 m/s . The ball and bat are in contact for 1.73 ms .

Find the horizontal and vertical components of the average force on the ball. Let +x be to the right and +y be upward

Express your answers using three significant figures separated by a comma.

Answer 1

Answer:

Given:  mass of baseball = 0.145 kg

ball is traveling horizontally to the right 39.0 m/s

solution:

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The avg force on the ball is the ball's change in momentum divided by time;

F(x) = [mV(x)f - mV(x)i]/t

= (.145)[-59Cos(29) - 39]/(.00173)

= -7593.856 N

F(y) = [mV(y)f - mV(y)i]/t

= (.145)[59Sin(29) - 0]/(.00173)

= 2397.426 N

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