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At the end of a race, a runner decelerates to a stop from a velocity of...

At the end of a race, a runner decelerates to a stop from a velocity of 8 m/s at a rate of 1.88 m/s2. How far does she travel in 8.6 s from when she begins decelerating?

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Answer #1

Using

v = u + at

a = -1.88 m/s2

t = 8.6 s

u = 8 m/s

v2 - u2 = 2as

Stopping distance = 17.02 m

Please rate it up thanks :)

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