Question

In Java Programming chapter 6

Make a class that represents a file. This class will have the ability to calculate the number of lines in that file and the ability to search through the file.

UML diagram:

-filename:String

+FileStats(String fname)

+getNumMatchingWords(String wordtoFind) : int

+getNumLines() : int

The getNumMatchingWords method will take a bit of text and determine how many lines contain that text. Make the comparison not care about case.

View required output

Test Case 1

Files in the same directory
bill-of-rights.txt dictionary.txt romeo-and-juliet.txt FileStatsDemo.java

Num lines in Bill of Rights: 65\n
Num lines in Romeo and Juliet: 5268\n
Num lines in dictionary: 21882\n
-- Bill of Rights Test --\n
'the' count: 29\n
'no' count: 17\n
'rights' count: 2\n
-- Romeo and Juliet Test --\n
'Romeo' count: 304\n
'Juliet' count: 185\n
'end' count: 95\n
'emoji' count: 0\n

here how the demo looks like

import java.io.FileNotFoundException;

public class FileStatsDemo
{
    public static void main(String[] args) throws FileNotFoundException {

        FileStats billOfRights = new FileStats("bill-of-rights.txt");
        FileStats romeoAndJuliet = new FileStats("romeo-and-juliet.txt");
        FileStats dictionary = new FileStats("dictionary.txt");

        System.out.println("Num lines in Bill of Rights: " + billOfRights.getNumLines());
        System.out.println("Num lines in Romeo and Juliet: " + romeoAndJuliet.getNumLines());
        System.out.println("Num lines in dictionary: " + dictionary.getNumLines());

        System.out.println("-- Bill of Rights Test --");
        System.out.println("'the' count: " + billOfRights.getNumMatchingWords("the"));
        System.out.println("'no' count: " + billOfRights.getNumMatchingWords("no"));
        System.out.println("'rights' count: " + billOfRights.getNumMatchingWords("rights"));

        System.out.println("-- Romeo and Juliet Test --");
        System.out.println("'Romeo' count: " + romeoAndJuliet.getNumMatchingWords("ROMEO"));
        System.out.println("'Juliet' count: " + romeoAndJuliet.getNumMatchingWords("juliet"));
        System.out.println("'end' count: " + romeoAndJuliet.getNumMatchingWords("end"));
        System.out.println("'emoji' count: " + romeoAndJuliet.getNumMatchingWords("emoji"));

    }
}

Answer 1

import java.io.BufferedReader;
import java.io.File;
import java.io.FileNotFoundException;
import java.io.FileReader;
import java.io.IOException;
import java.io.LineNumberReader;

public class FileStartsDemo {
public String fileName;

public FileStartsDemo(String fileName) {
   this.fileName = fileName;
}

   public int getNumMatchingWords(String inputSearch) {
      
       double countBuffer=0;
       int lineNumber=0;
       BufferedReader br;
       String line = "";
try {
   br = new BufferedReader(new FileReader(fileName));

while((line = br.readLine()) != null){

String[] words = line.split(" ");

for (String word : words) {
if (word.equals(inputSearch)) {
countBuffer++;
}
}

if(countBuffer > 0) {
countBuffer = 0;
lineNumber++;
}
}
br.close();
} catch (IOException e) {
e.printStackTrace();
}
return lineNumber;
}
  
   public int getNumLines() {
      
   int lineNumber = 0;

       try{
           File file=new File(fileName);
       if(file.exists()){
          
       FileReader fr = new FileReader(file);
       LineNumberReader lnr = new LineNumberReader(fr);
      
      
   while (lnr.readLine() != null){
       lineNumber++;
   }
   lnr.close();
  
       }else{
           System.out.println("File does not exists!");
       }
      
   }catch(IOException e){
       e.printStackTrace();
   }
       return lineNumber;
   }

   public static void main(String[] args) throws FileNotFoundException{
      
       FileStartsDemo c = new FileStartsDemo("C:\\Users\\durga.chityala\\Desktop\\abc.txt");
  
       System.out.println("-----abc-----");
       System.out.println("number of lines in abc: "+c.getNumLines());
       System.out.println("java count: "+c.getNumMatchingWords("java"));

   }
}