Question

Write a C++ program divisorsum.cpp which which reads numbers, one at a time, from the terminal input, and outputs the proper divisors and the proper divisor sum for that integer in an equation format.

Here is an example:

> divisorsum
6
6: 1+2+3 = 6
888
888: 1+2+3+4+6+8+12+24+37+74+111+148+222+296+444 = 1392
0
>

Note: spaces will be ignored, but punctuation symbols (:+=) must be in the correct places.

Your program should handle the calculation of proper divisor sums for all numbers between 2 and 2147483647.

Your program should continue answering about the proper divisor sums of numbers until 0 is entered, at which time the program should exit silently.

Answer 1

Hello, here is the completed code you wanted. Every important statement is explained using comments. Please check and let me know if you have any doubts. Thanks.

CODE

#include<iostream>

using namespace std;

//main function
int main()
{
   int number;
   unsigned int sum;
      
   //repeat until number is 0
   while(true)
   {
       //prompt for number
       cout<<"\nEnter a number: ";
       cin>>number;
      
       //if number is zero
       if(number == 0)
           //break from the loop
           break;
      
       //initialize sum as 1
       sum = 1;
      
       //printing number and 1
       cout<<number<<": 1";
      
       for(int i = 2; i < number; i++)
       {
           //if i is a proper divisor of number
           if(number % i == 0)
           {
               //print + and i
               cout<<"+"<<i;
              
               //calculating sum
               sum = sum + i;
           }
       }
       //printing sum
       cout<<" = "<<sum;
   }
}

OUTPUT

CODE SCREEN SHOT