A)
Suppose an equilibrium mixture consists of 0.68 atm N2O4 and 2.1 atm NO2, and the volume of the container is halved at constant temperature. Calculate the new equilibrium pressure (atm) of NO2.
B)
NaCl(s) ⇌ Na+(aq) + Cl-(aq) ΔHo = 3.9 kJ/mol
At 298 K, a saturated solution of NaCl has [Na+] = 7.0 M and [Cl-] = 5.4 M. If the temperature of the mixture is increased to 321 K, what will be the equilibrium concentration (M) of Na+? (Assume no ion pairing.) Enter your answer to 2 decimal places.
C)
Consider this reaction: N2(g) + 3 H2(g) ⇌ 2 NH3(g) ΔHo = −92 kJ/mol
Using a catalyst for this reaction will effect all the changes below except one. Which one?
increased NH3 yield
increased rate of N2 formation
increased rate of NH3 formation
A) Suppose an equilibrium mixture consists of 0.68 atm N2O4 and 2.1 atm NO2, and the...
Suppose an equilibrium mixture consists of 0.74 atm N2O4 and 2.6 atm NO2, and the volume of the container is halved at constant temperature. Calculate the new equilibrium pressure (atm) of NO2. NaCl(s) ⇌ Na+(aq) + Cl-(aq) ΔHo = 3.9 kJ/mol At 298 K, a saturated solution of NaCl has [Na+] = 7.0 M and [Cl-] = 5.4 M. If the temperature of the mixture is increased to 326 K, what will be the equilibrium concentration (M) of Na+? (Assume...
Suppose an equilibrium mixture consists of 0.42 atm N2O4 and 2.4 atm NO2, and the volume of the container is halved at constant temperature. Calculate the new equilibrium pressure (atm) of NO2.
Suppose an equilibrium mixture consists of 0.46 atm N2O4 and 2.0 atm NO2, and the volume of the container is halved at constant temperature. Calculate the new equilibrium pressure (atm) of NO2. Please show me how to solve??
NaCl(s) ⇌ Na+(aq) + Cl-(aq)
ΔHo = 3.9 kJ/mol At 298 K, a saturated solution of NaCl has [Na+] =
7.0 M and [Cl-] = 5.4 M. If the temperature of the mixture is
increased to 323 K, what will be the equilibrium concentration (M)
of Na+? (Assume no ion pairing.) Enter your answer to 2 decimal
places.
NaCl(s) Na (aq) + CI'(aq) AH- 3.9 kJ/mol At 298 K, a saturated solution of NaCI has [Na"] 7.0M and [CI] -...
15. Consider the reaction 2 NO2(g)
N2O4(g) .
(a) Using Gf
N2O4(g) = 97.79 kJ/mol and Gf NO2(g)
= 51.3 kJ/mol, calculate G° at 298 K.
kJ
(b) Calculate G at 298 K if the partial pressures of
NO2 and N2O4 are 0.35 atm and 1.60
atm, respectively.
kJ
16. Consider the reaction given below.
H2(g) + F2(g)
2 HF(g)
(a) Using thermodynamic data from the course website, calculate
G° at 298 K.
kJ
(b) Calculate G at 298 K...
Consider the reaction 2 NO2(g) N2O4(g) . (a) Using ΔGf N2O4(g) = 97.79 kJ/mol and ΔGf NO2(g) = 51.3 kJ/mol, calculate ΔG° at 298 K. ______ kJ (b) Calculate ΔG at 298 K if the partial pressures of NO2 and N2O4 are 0.45 atm and 1.55 atm, respectively. _____ kJ
1) Kc = 45 for the equilibrium : 2 NO2(g) <====> N2O4 (g) at a temperature 85 C a) What is Kc for N2O42 <====> NO2(g) ? b) What is Kp for 2 NO2(g) <====> N2O4 (g) at 85 C? R= 0.0821 L-atm/ k-mol 2) The pH of seawater is 8.10 This corresponds to ________ M H+
Consider the reaction 2 NO2(g) →N2O4(g) .(a) Using ΔGfN2O4(g) = 97.79 kJ/mol and ΔGf NO2(g) = 51.3 kJ/mol, calculate ΔG° at 298 K.kJ(b) Calculate ΔG at 298 K if the partial pressures of NO2 and N2O4 are 0.25 atm and 1.30 atm, respectively.kJ
A flask is charged with 1.500 atm of N2O4(g) and 0.94 atm NO2(g) at 25°C. The equilibrium reaction is given in the equation below. N2O4(g) 2NO2(g) After equilibrium is reached, the partial pressure of NO2 is 0.512 atm. (a) What is the equilibrium partial pressure of N2O4? ______ atm (b) Calculate the value of Kp for the reaction. ______ (c) Is there sufficient information to calculate Kcfor the reaction? -Yes, because the temperature is specified. -No, because the value of...
What is the numerical value of Kc for the following reaction if the equilibrium mixture contains 0.055 M N2O4 and 0.34 M NO2? N2O4 (g) ===== 2NO2 (g)