Find the Ka value for 0.005L of unknown acid (0.2005M) mixed with 0.0025L of NaOH (0.1005M). Then 0.0125L of H2O is added for a total volume of 0.02L. The solution pH = 4.6.
I found that Ka=1.2*10^-8 and just want to make sure I did my math right. Thanks!
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Find the Ka value for 0.005L of unknown acid (0.2005M) mixed with 0.0025L of NaOH (0.1005M)....
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calculations for:
concentration of the unknown acid and values for pKa and
Ka.
Part E: pH pH pH pH Average Volume Trial 1 Trial 2 Trial 3 5.0 0 5 5.0। 5.1 .0 । 5.1 5.1 5.2 5.3 [5.0। 5.1 5.1 5.1 5.2 5.3 [5.2 5.3 5.3 5.4 5.5 16. 16.5 17.0 | 17.5। 18.0 18.5 19.0 19.5 | 20.0 20.5 21.0 | 21.5 | 22.0 22.5 23.0 23.5 24.0 24.5 | 5.6 5.7 [5.3 [5.4 | 5.5 | 5.6...