Use technology to find the P-value for the hypothesis test described below.
The claim is that for a smartphone carrier's data speeds at airports, the mean is
muμequals=17.00 Mbps. The sample size is n=14 and the test statistic is t=-1.992
P-value equals=?
(Round to three decimal places as needed.)
Solution:
This is two tailed test.
n = 14
Degrees of freedom (df) = n - 1 = 13
Test statistic (t) = -1.992
P-value = (tdf < -1.992)
P-value = 0.068
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