A beam of electrons of energy 2.0 keV is injected at right angles into an electric field of 5.0 kV/m. Calculate the linear deviation of the beam when it has travelled a distance of 10.0 cm in the field. (the answer is .63 cm)
Concept - find the speed of electron using the
kinetic energy of the electron given. In horizontal direction the
electron travels a distance of 10 cm. We use this to find the
required time. In vertical direction we find the acceleration using
the electric field as shown below and use equation of kinematics to
find the vertical deviation.
***********************************************************************************************
This concludes the answers. If there is any mistake or
omission, let me know immediately and I will fix
it....
A beam of electrons of energy 2.0 keV is injected at right angles into an electric...
A beam of electrons with kinetic energy of 1 keV passes through a slit of width a = 1 micro-m. The electron beam is then detected on a phosphorescent scree loacted at a distance D = 1 m from the slit. What is the width W of the "image" of the electron beam?
The electron beam in a typical scanning electron microscope produces kinetic energies of 27.0 keV (a) Assuming that relativistic effects can be ignored, what is the speed of the electrons? Number m/s (b) What potential difference is required to produce electrons of this energy? Number Units (c) This accelerating potential difference is applied over a distance of 1.80 cm. What is the electric field in that region? Number Units
In a cathode-ray tube, a beam of electrons (the cathode ray) is deflected in a region of electric field on its way to a fluorescent screen, as shown in the figure. Consider the parallel-plate arrangement in the figure, and assume that the electric field E = 400 N/C is uniform between the plates and that E = 0outside the plates. The beam of electrons is injected horizontally with velocity v0 = 5.0 × 106 m/s. If the width of the...
please show explanation! thank you
Each of the electrons in the beam of a television tube has a kinetic energy of 10.0 keV. The tube is oriented so that the electrons move horizontally from north to south. The vertical component of Earth's magnetic field points down and has a magnitude of 52.0 ut. (Ignore the northward component of Earth's field.) In what direction will the electron beam deflect? O north O east O west o down O up south Submit...
The electron beam in a typical scanning electron microscope produces kinetic energies of 22.0 keV. (a) Assuming that relativistic effects can be ignored, what is the speed of the electrons? 8.791 10m/s (b) What potential difference is required to produce electrons of this energy? Number Units (c) This accelerating potential difference is applied over a distance of 2.00 cm. What is the electric field in that region? NumberUnits
Each of the electrons in a particle beam has a kinetic energy of 1.18 ✕ 10^−17 J. (a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' movement) that will stop these electrons in a distance of 13.5 cm? N/C (b) How long will it take to stop the electrons? ns (c) After the electrons stop, the electric field will continue to act on them, causing the electrons to accelerate in a direction...
Each of the electrons in a particle beam has a kinetic energy of
1.36 ✕ 10−17 J. The mass of an electron is 9.11 ✕
10−31 kg.
(a) What is the magnitude of the uniform electric field
(pointing in the direction of the electrons' movement) that will
stop these electrons in a distance of 11.0 cm?
N/C
(b) How long will it take to stop the electrons?
ns
(c) After the electrons stop, the electric field will continue to
act...
Each of the electrons in the beam of a television tube has a kinetic energy of 13.0 keV. The tube is oriented so that the electrons move horizontally from geomagnetic south to geomagnetic north. The vertical component of Earth's magnetic field points down and has a magnitude of 48.0 μT. In what direction will the beam deflect? (north, south, east, west, up, down) What is the acceleration of a single electron due to the magnetic field? How far will the...
Each of the electrons in a particle beam has a kinetic energy of 1.08 x 10-17 3. The mass of an electron is 9.11 x 10-31 kg. (a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' movement) that will stop these electrons in a distance of 16.5 cm? N/C (b) How long will it take to stop the electrons? 4.9 ns (c) After the electrons stop, the electric field will continue to...
Each of the electrons in a particle beam has a kinetic energy of 1.42 ✕ 10−17 J. The mass of an electron is 9.11 ✕ 10−31 kg. (a) What is the magnitude of the uniform electric field (pointing in the direction of the electrons' movement) that will stop these electrons in a distance of 14.0 cm? (b) How long will it take to stop the electrons? (c) After the electrons stop, the electric field will continue to act on them,...