Question

Complete the code so that the program makes the expected output. Use no more than one word in the blank.

Expected output: adam_smith

for ch in "adam_smith@openedg.org":

if ch == "@":

_________

print(ch, end="")

Answer 1

The answer to the question is given below.

At blank space, we have to write break.
It will terminate the for loop when ch is @

The python code is given below.

for ch in "adam_smith@openedg.org":
   if ch=="@":
       break
   print(ch,end="")

The screenshot of the running code is given below.



The screenshot of the output is given below.





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