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At 248 ºC and a total pressure of 1.00 atm the degree of dissociation of SbCl5(g)...

At 248 ºC and a total pressure of 1.00 atm the degree of dissociation of SbCl5(g) is alpha = 0.718 for the reaction

SbCl5(g) ↔ SbCl3(g) + Cl2(g) .

The degree of dissociation alpha is defined as:

alpha = (number of moles of SbCl5 dissociated at equilibrium) / (original number of moles of SbCl5) .

(a) What is the value of the equilibrium constant K(T) at 248 ºC and 1.00 atm?

(b) What is the value of Kx (the equilibrium constant expression expressed in terms of mol fractions) at the same temperature when the pressure is 5.00 atm? Assume that under these conditions the system at equilibrium behaves as an ideal gas mixture.

(c) What is the value of the degree of dissociation alpha in the conditions of part (b)?

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