Demand for oil changes at Garcia's Garage has been as follows:
|
Month |
Number of Oil Changes |
|
January |
43 |
|
February |
51 |
|
March |
63 |
|
April |
50 |
|
May |
60 |
|
June |
42 |
|
July |
68 |
|
August |
72 |
a. Use simple linear regression analysis to develop a forecasting model for monthly demand. In this application, the dependent variable, Y, is monthly demand and the independent variable, X, is the month. For January, let
Xequals=1;
for February, let
Xequals=2;
and so on.
The forecasting model is given by the equation
Yequals=+X.
(Enter your responses rounded to two decimal places.)
|
PERIOD |
DEMAND |
X |
Y |
XY |
X^2 |
|
1 |
43 |
1 |
43 |
43 |
1 |
|
2 |
51 |
2 |
51 |
102 |
4 |
|
3 |
63 |
3 |
63 |
189 |
9 |
|
4 |
50 |
4 |
50 |
200 |
16 |
|
5 |
60 |
5 |
60 |
300 |
25 |
|
6 |
42 |
6 |
42 |
252 |
36 |
|
7 |
68 |
7 |
68 |
476 |
49 |
|
8 |
72 |
8 |
72 |
576 |
64 |
|
SIGMA |
36 |
449 |
2138 |
204 |
INTERCEPT(B0) = (SIGMA(Y) * SIGMA(X^2) - SIGMA(X) * SIGMA(XY)) / (N * SIGMA(X^2) - SIGMA(X)^2)
INTERCEPT = (449 * 204) - (36 * 2138) / ((8 * 204) - 36^2) = 43.54
SLOPE(B1) = ((N * SIGMA(XY)) - (SIGMA(X) * SIGMA(Y))) - (N * SIGMA(X^2) - SIGMA(X)^2)
SLOPE = ((8 * 2138) - (36 * 449) / ((8 * 204) - 36^2) = 2.8
EQUATION
Y = INTERCEPT + SLOPE(X)
Y = 43.54 + (2.8 * (X))
FOR X = 9(SEPTEMBER), FORECAST = 43.54 + (2.8 * 9) = 68.74
Demand for oil changes at Garcia's Garage has been as follows: Month Number of Oil...
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