Question

• collatz

  public static int[] collatz(int start,
                              int numIterations)

  Given integer start and integer numIterations, return an array containing the Collatz sequence beginning with start up to numIterations. The Collatz function is defined by: 3n + 1 if n is odd n/2 if n is even Given start = 7 and numIterations = 3, this method returns [7, 22, 11, 34]

  Parameters:

  start - starting integer

  numIterations - how long to compute the Collatz sequence for

  Returns:

  an array containing the Collatz sequence beginning with start up to numIterations.

Answer 1

public class Collatz {
   public static void main(String[] args) {
       int arr[]=collatz(7, 3);
       for(int x:arr)
           System.out.print(x+" ");
       int [][]a= {{1,2},{3,4},{5,6}};
       int sum=0;
       for(int i=0;i<a.length;i++)
           sum+=a[i][0];
       System.out.println(sum);
   }

   public static int[] collatz(int start, int numIterations) {
       int arr[] = new int[numIterations + 1];
       arr[0]=start;//first num will be starting only
      
       for (int i = 1; i < 4; i++) {
           //checking if it odd than 3n+1 else n/2
               if(start%2==1)
                   start=start*3+1;
               else
                   start=start/2;
               arr[i]=start;
       }

       return arr;
   }
}

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