Question

Write a function to find the smallest odd number in a list. The function takes a list of numbers (each number is greater than or equal to 0) as an input. The function outputs a tuple, where the first number in the tuple is the smallest odd number and the second number in the tuple is the number of occurrences of that number.

For example, if the input is [1, 4, 7, 3, 5, 2, 1, 3, 6] then the output should be the tuple (1, 2)

Python please thanks

Answer 1

#a function to find the smallest odd number in a list.
#return a tuple, smallest number and its count
def smallest_ODDnum(l):
if len(l)==0:#if list is empty
return ()#returning empty tuple
s=-1#to store smallest odd number
c=0#to store count
for i in l:
if i%2==1:#if odd number
if c==0:
c+=1
s=i
else:
if i<s:#smaller than current smallest number
c=1
s=i
elif i==s:
c+=1
return (s,c)
#testing above method
print(smallest_ODDnum([1,4,7, 3, 5, 2, 1, 3, 6]))
print(smallest_ODDnum([3,4,2,7,2, 3,1, 5, 2,1,0,3, 6,0,0,1]))