Given the reference thermodynamic data below taken at 25°C,
calculate the value of the equilibrium constant for the reaction
shown at 800.0ºC
COCl2 (g) ⇄ CO (g) + Cl2 (g)
ΔGº = 69.46 kJ
ΔHº = 110.38 kJ
ΔSº = 137.24 J/K
K = Answer at 800.0ºC
Given the reference thermodynamic data below taken at 25°C, calculate the value of the equilibrium constant...
Given the reference thermodynamic data below taken at 25°C, calculate the value of the equilibrium constant for the reaction shown at 800.0°C COCI, (g) 2 CO (g) + Cl2 (g) AG° = 69.46 kJ AH° = 110.38 kJ AS° = 137.24 J/K at 800.0°C
Given the thermodynamic data below, calculate the value of the equilibrium constant for the reaction shown at 25.0ºC H₂ (g) + I₂ (g) ⇄ 2 HI (g) ΔHº = -9.48 kJ ΔSº = +21.79 J/K K = Answer at 25.0ºC
Given the thermodynamic data below, calculate the value of the
equilibrium constant for the reaction shown at 25.0ºC
H₂ (g) + I₂ (g) ⇄ 2 HI (g)
Given the thermodynamic data below, calculate the value of the equilibrium constant for the reaction shown at 25.0°C H2(g) + 12 (g) = 2 HI(g) AH° = -9.48 kJ AS° = +21.79 J/K K= at 25.0°C Check
Calculate the value of the free energy change, ΔG, for the reaction below at 227.0ºC when the pressures of NO (g) = 2.00 atm, O₂ (g) = 10.00 atm, and NO₂ (g) = 0.0250 atm. 2 NO (g) + O₂ (g) → 2 NO₂ (g) ΔGº = -70.54 kJ ΔHº = -114.14 kJ ΔSº = -146.43 J/K ΔG = ? kJ
Calculate the value of the free energy change, ΔG, for the reaction below at 175.0ºC when the pressures of H2S (g) = 0.0100 atm, SO2(g) = 0.0250 atm, and H2O (g) = 2.50 atm. 2 H2S (g) + SO2 (g) → 3 S (s) + 2 H2O (g) ΔGº = –90.88 kJ ΔHº = –146.47 kJ ΔSº = –186.45 J/K
Calculate the value of the free energy change, ΔG, for the reaction below at 150.0ºC when the pressures of H2S (g) = 0.0200 atm, SO2(g) = 0.400 atm, H2O (g) = 5.00 atm. 2 H2S (g) + SO2 (g) → 3 S (s) + 2 H2O (g) ΔGº = –90.88 kJ ΔHº = –146.47 kJ ΔSº = –186.45 J/K ΔG = Answer kJ
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 641 K for the following reaction. NH4Cl(s) NH3(g) + HCl(g) ΔΗ /kJ mol-1 -314.4 -45.9 -92.3 Smº /JK-mol-1 94.6 192.8 186.9 Cp.m /JK-mol-1 84.1 35.1 29.1 Do not use the Van't Hoff equation, In(K/K) = -(AHR/R) (T2-1-T1-1) The value of the thermodynamic equilibrium constant is Kp = Number
Use the data below, for 298.15 K, to calculate the thermodynamic equilibrium constant, kp, at 839 K for the following reaction. NH4Cl(s) NH3(g) + HCl(g) ΔΗ 7 kJ mol-1 -314.4 -45.9 -92.3 Smº JK-1 mol-1 94.6 192.8 186.9 Cp,m 84.1 35.1 29.1 /JK-1 mol-1 Do not use the Van't Hoff equation, In(K /K1) = -(AHR/R) (T2-1 - 7,-1) The value of the thermodynamic equilibrium constant is Kp= 7.6e14
1) Calculate the equilibrium constant at 138 K for the thermodynamic data in the previous question. Notice that Keq is larger at the larger temperature for an endothermic reaction. 2) Endothermic reaction; increase in entropy Calculate the equilibrium constant at 40 K for a reaction with ΔHrxno = 10 kJ and ΔSrxno = 100 J/K.
Calculate the equilibrium constant from the standard free energy change. Using standard thermodynamic data (linked), calculate the equilibrium constant at 298.15 K for the following reaction. H2(g) + Cl2(g)—>2HCI(g) K=