Question

5.   Consider base 2.

 What is log 128

 What is log 256

 what is log 64

What is log 32

 

6.   Draw the diagram showing a function is injective

 

7.  Draw the diagram showing a function surjective

 

8.  What is the

     floor of  sqrt ( 2)  =   

     ceiling of 28/6,   = 

     floor of  sqrt ( 5 ) =

     ceiling of 32/3 =

Answer 1

`Hey,

Note: Brother if you have any queries related the answer please do comment. I would be very happy to resolve all your queries.

5)

a)

log(128)=log(2^7)=7*log(2)

We know that log(2) is 1

So,

log(128)=7

b)

log(256)=log(2^8)=8*log(2)

We know that log(2) is 1

So,

log(256)=8

c)

log(64)=log(2^6)=6*log(2)

We know that log(2) is 1

So,

log(64)=6

d)

log(32)=log(2^5)=5*log(2)

We know that log(2) is 1

So,

log(32)=5

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