What is the minimum work needed to push a 850 -kg car 840 m up along a 9.5 ∘ incline?
Work needed will be equal to change in potential energy of car.
Work= mgh (where h is vertical height)
= 850*9.8*840*sin(9.5°)
=1154871.108 Joules
What is the minimum work needed to push a 850 -kg car 840 m up along...
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A mass m = 17 kg is pulled along a horizontal floor with NO
friction for a distance d =6 m. Then the mass is pulled up an
incline that makes an angle θ = 37° with the horizontal and has a
coefficient of kinetic friction μk = 0.4. The entire
time the massless rope used to pull the block is pulled parallel to
the incline at an angle of θ = 37° (thus on the incline it is
parallel...