Question

Two circular loops of wire, each containing a single turn, have the same radius of 3.90 cm and a common center. The planes of the loops are perpendicular. Each carries a current of 2.00 A. What is the magnitude of the net magnetic field at the common center?

Answer 1

Solution-:

Given data ;

N, no of turns in each loop = 1

Radius, r = 3.90 cm = 0.039 m

Current, I = 2.00 A

Then use formula is ,

B= μ0 N I / 2r

B = (4 pi *10^-7 Tm/A)(1)(2.0A) / 2(0.039m)

B = 3.22*10^-5 T

the net magnetic field at the center is ,

Bnet = square root (B^2+B^2)

Bnet = B * square root 2

Bnet = 4.55*10^-5 T (Answer)

I hope help you !!