Signals and system
A)Sketch the signal x(n)=u(n)-u(n-2)
B)Determine if signal sin3 (n) is periodic.
A)
only at n=0 and n=1 u(n) has value 1 everwhere else due to subtraction value is 0(ie, becomes 1-1=0).
The sketch is :
B)
Sin^{3}(n) is not periodic as sin has period so to become periodic n should be a multiple of at some point in time , but n can have only values which are rational (ex: 1,2,3,4 etc) n cant have irrational values (eg n cant be ).Thus function is not periodic.
Signals and system A)Sketch the signal x(n)=u(n)-u(n-2) B)Determine if signal sin3 (n) is periodic.
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