QUESTION 1
Variable(s) that affect rate include:
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temperature |
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concentration |
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pressure of gasses |
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All of the above |
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a and b only |
1 points
QUESTION 2
The rate constant (k) for a reaction:
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has units of M/s. |
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changes with temperature |
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is different for different concentrations of reactants |
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All of the above |
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b and c |
1 points
QUESTION 3
If a reactant is 2nd order, doubling the concentration of the reactant will:
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double the rate of the reaction |
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triple the rate of the reaction |
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quadruple the rate of the reaction |
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None of the above |
1 points
QUESTION 4
A rate law can be obtained:
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by graphing rate vs concentration. |
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by graphing M vs time |
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from the balanced chemical equation for the reaction. |
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Both a and b. |
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Both b and c. |
1 points
QUESTION 5
The order of a reaction is determined by:
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adding up the coefficients from the balanced equation |
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adding up the exponents in the rate law |
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dividing the rise by the run |
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All of the above. |
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Both a and b |
Question-1
Rate depends upon concentration, pressure,temper tempe
So all of the above is correct.
Question-2
Rate constant only depends only on temperature.(b) is correct.
Question-3
By doubling the concentration rate of quadruple the rate of reaction.
Question-4
Rate law can be obtained by graphing M v/s time
Question-5
The order of reaction is determined by adding up the exponents in the rate law
QUESTION 1 Variable(s) that affect rate include: temperature concentration pressure of gasses All of the above...
1. If the rate constant of a reaction increases by 2.5 when the temperature is increased from 25 C to 34 C, then what is the activation energy (in kJ/mole) of the reactions? 2. If a reaction is first order with a rate constant of 4.48 x 10 ^ -2 sec ^-1, how long is required for 3/4 of the initial concentration of reactant to be used up? 3. Which statement is true or NOT regarding the experimental determination of...
Most of the time, the rate of a reaction depends on the
concentration of the reactant. In the case of second-order
reactions, the rate is proportional to the square of the
concentration of the reactant.
Select the image to explore the simulation, which will help you
to understand how second-order reactions are identified by the
nature of their plots. You can also observe the rate law for
different reactions.
In the simulation, you can select one of the three different...
Consider the following reaction and its associated rate law A + B - C; rate = k[A]2 Which of the following will not increase the rate of the reaction? Select one: a. increasing the concentration of reactant A O b. increasing the concentration of reactant B O c. increasing the temperature of the reaction d. adding a suitable catalyst O e. all of the above
± Using Integrated Rate Laws Part A The reactant concentration in a zero-order reaction The integrated rate laws for zero-, first-, and second order reaction may be arranged such that they resemble the equation for a straight line y=mx + b was 9.00x102 M after 155 s and 3.50x102 M after 320 s. What is the rate constant for this reaction? Express your answer with the appropriate units Indicate the multiplication of units, as necessary explicitly either with a multiplication...
Solve all
(b) Temperature 4th tha YE be canse how can the temperature affect the rate of a reaction 0 V) The following reaction mechanism has been pr reactions (22 ps) proposed for a F 2F fast CFBr, fast (1) What is the overall chemical reaction equation 7 (2) Which are the intermediates 7teet (3) What is the rate law that corresponds to the above mechanism (4) If the overall reaction above is an endothermic reaction. Draw an reaction coordinate...
The reactant concentration in a zero-order reaction was 0.100
M after 165 s and 2.50×10−2M after 345
s, and the rate constant of the reaction is 4.17*10
What was the initial reactant concentration for the reaction
described in Part A?
Express your answer with the appropriate units. Indicate the
multiplication of units, as necessary, explicitly either with a
multiplication dot or a dash.
The integrated rate laws for zero-, first-, and second-order may be arranged such that they resemble the...
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute [A]02 for [A] and rearrange the equation to: t1/2=0.693k This equation calculates the time...
Select all that apply. The rate law for the reaction 2NO(g) + Cl2(g) → 2NOCI(g) is given by R-k[NO][C121 If the following is the mechanism for the reaction, NO(g) + Cl2(g) → NOC12(g) NOCI,(g) + NO(g) → 2NOCI(g) which of the following statements accurately describes this reaction? Check all that apply. 2nd order reaction The first step is the slow step. Doubling [NO] would quadruple the rate. Cutting (Cl) in half would decrease the rate by a factor of two....
The integrated rate law allows chemists to predict the reactant concentration after a certain amount of time, or the time it would take for a certain concentration to be reached. The integrated rate law for a first-order reaction is: [A]=[A]0e−kt[A]=[A]0e−kt Now say we are particularly interested in the time it would take for the concentration to become one-half of its initial value. Then we could substitute [A]02[A]02 for [A][A] and rearrange the equation to: t1/2=0.693k t1/2=0.693k This equation calculates the...
The integrated rate law allows
chemists to predict the reactant concentration after a certain
amount of time, or the time it would take for a certain
concentration to be reached. The integrated rate law for a
first-order reaction is: [A]=[A]0e−kt Now say we are particularly
interested in the time it would take for the concentration to
become one-half of its initial value. Then we could substitute
[A]02 for [A] and rearrange the equation to: t1/2=0.693k This
equation calculates the time...