Question

Oxidation of ammonia by chlorine may produce various compounds such as: NO(g), N2O4(g), N2H4(aq), N2(g), N2O(g),...

Oxidation of ammonia by chlorine may produce various compounds such as: NO(g), N2O4(g), N2H4(aq), N2(g), N2O(g), NO2-(aq), NO3-(aq) and NH2OH(aq).

  1. For this case, arrange such compounds according to the oxidation state of the nitrogen contained in each one.
  2. Fill-in the following table with the requested formulas and the stoichiometric coefficients that correspond to the theoretical oxidation with elemental chlorine of each nitrogenated species (symbolized as X), as in the generalized equation:

                                          aNH3(aq) + bCl2(g) + cH2O(l) = X + yCl-(aq) + zH3O+(aq)

        (The case of N2O is given as an example: 2NH3(aq) + 4Cl2(g) + 9H2O(l) = N2O(g) + 8Cl-(aq) + 8H3O+(aq))

Oxidation state of N in X

Formula of X

a

b

c

y

z

Moles of Cl2 reduced/moles of ammonia nitrogen

-2

-1

0

+1

N2O

2

4

9

8

8

4/2=2

+2

+3

+4

+5

[1] Ibañez-Jorge G et.al. (2008) Environmental Chemistry. Springer. USA

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Answer #1

the oxidation state of NO is+1 or+2,N2O4 IS+4,NH2OH is -1,NO3 is -2,NO2 is +4, N2O is +1,N2 is 0,and N2H4 is +3.

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