A 9.59 μF capacitor is charged to 3.41×103 V and is then connected in series with...
A 9.59 μF capacitor is charged to 3.41×103 V and is then connected in series with a 75.0 Ω resistor and a 6.15 Ω resistor. How much energy is dissipated by the 75.0 Ω resistor if the resistors are allowed to discharge completely? Answer in Joules please.
Homework Answers
Energy, E = 0.5 CV^2
E = 0.5 x (75/81.15) x (9.59 x 10^-6) x 3410^2
E = 52.07 J
Comment in case any doubt please rate my answer.....
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