Write a C program that will produce the EXACT output shown below.
Your C program should take the data in the arrays and produce the output below, neatly formatted as shown
Enter a sentence: My cat’s name is Bella.
You sentence includes:
Number of words: 5
Number of spaces: 4
Number of vowels: 6
Number of consonants and special characters: 13
C CODE
#include<stdio.h>
#define MAX 1000 // DEFINE MAX LENGTH OF CHARACTERS ARRAY
int main()
{
char str[MAX]; // CHARACTER ARRAY OR STRING TO HOLD
THE INPUT STRING
int i; // INDEX VARIBLE
// DECLARE ALL COUNT VARIABLES AND INITIALIZE WITH 0
int words=0;
int spaces=0;
int vowel=0;
int consonant=0;
int special=0;
int aplhbate=0;
// ACCEPT THE STRING FROM USER
printf("Enter the string : ");
scanf("%[^\n]",str);
//ITERATE THE STRING UPTO NULL CHARACTER. '\0' OR NULL
IS TERMINATING CHARACTER OF A STRING
// INSTEAD OF '\0' NULL MAY BE USED DEPEND UPON
COMPILER
for(i=0; str[i]!='\0'; i++)
{
// COMPARE EACH CHARACTER FOR
SPACE.
if( str[i]==32)
{
spaces++;
}
// COMPARE EACH CHARACTER FOR
VOWEL , WHETHER UPERR CASE OR LOWER CASE
if( str[i]=='a' || str[i]=='A' ||
str[i]=='e' || str[i]=='E' || str[i]=='i' || str[i]=='I'||
str[i]=='o' || str[i]=='O' || str[i]=='u' || str[i]=='U')
{
vowel++;
}
// COMPARE EACH CHARACTER TO
CHECK ALPHABATE
if( (str[i]>='a' &&
str[i]<='z') || (str[i]>='A' && str[i]<='Z')
)
{
aplhbate++;
}
}
// NUMBER OF WORDS WILL BE 1 MORE THAN NO. OF
SPACES.
words=spaces+1;
// GET NO OF CONSONANT
consonant= aplhbate- vowel;
//GET NO OF CPECIAL CHARACTER
// 'i' IS INDEX VARIABLE FOR THE STRING, NOW IT IS
HOLDING THE STRING LENGTH
// DIRECTLY TOTAL OTHER CHARACTERS(consonants and
special) CAN BE ALSO FOUND AS : i - (vowel+spaces)
special=i- (aplhbate+spaces);
//PRINT THE COUNTRS
printf("\n Number of words : %d ", words);
printf("\n Number of Spaces : %d ", spaces);
printf("\n Number of Vowels : %d ", vowel);
printf("\n Number of consonants and special characters: %d ", special+consonant );
return 0;
} // END OF MAIN
SCREEN SHOT CODE


SCREEN SHOT OUTPUT

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