Question

Prompt for a sequence of numbers, the last number being zero. Print the number many elements of this sequence are greater than their previous neighbor. (Code without using True or False values)

Example Input

Enter a Number (zero to quit): 1 
Enter a Number (zero to quit): 5 
Enter a Number (zero to quit): 2 
Enter a Number (zero to quit): 4
Enter a Number (zero to quit): 3
Enter a Number (zero to quit): 0

Example Output

Number of Values Greater Than the Previous: 2

python, sorry. But I believe I got figured out now.

thank you!

Answer 1

num = 1
previous = 0
i = 0
count = 0

while num != 0:
    num = int(input("Enter a Number (zero to quit): "))
    if num != 0:
        if i == 0:
            previous = num
        if num > previous:
            count += 1
        i += 1
        previous = num

print("Number of Values Greater Than the Previous:", count)