If ΔHΔHDH = -50.0 kJkJ and ΔSΔSDS = -0.300 kJ/KkJ/K , the reaction is spontaneous below...

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Question

If ΔHΔHDH = -50.0 kJkJ and ΔSΔSDS = -0.300 kJ/KkJ/K , the reaction is spontaneous below a certain temperature. Calculate that temperature.

Express your answer numerically in kelvins.

science chemistry

Answer 1

Answer #1

Answer 2

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